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2q^2-5q-512=0
a = 2; b = -5; c = -512;
Δ = b2-4ac
Δ = -52-4·2·(-512)
Δ = 4121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{4121}}{2*2}=\frac{5-\sqrt{4121}}{4} $$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{4121}}{2*2}=\frac{5+\sqrt{4121}}{4} $
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